Задание 10.6

Question

Найдите значение выражения $\sin (-30°) — 2tg	ext{ }(-45°) + \cos (-45^{\circ}).$

Gimli · Accepted Answer

$$\sin (-30°) - 2tg	ext{ }(-45°) + \cos (-45^{\circ}) = -\sin 30^{\circ} + 2tg	ext{ }45^{\circ} + \cos 45^{\circ} = -\frac{1}{2} +  2 + \frac{\sqrt{2}}{2} = 1\frac{1}{2} + \frac{1}{\sqrt{2}}.$$
	extbf{Ответ: $1\frac{1}{2} + \frac{1}{\sqrt{2}}.$}

Задание 10.6

Answers

Comments

Задание 10.6

Answers

Comments

Add answer