Задание 11.1

Найдите значения выражения:

1)sin 390;4)tg (210);

2)tg 780;5)cos 300;

3)sin (390);6)sin 5π 3 .

Answers

[10px,border : 3pxsolidblue]sin (x 2πn) = sin x = sin (x + 2πn).

[10px,border : 3pxsolidblue]cos (x 2πn) = cos x = cos (x + 2πn).

[10px,border : 3pxsolidblue]tg (x 2πn) = tg x = tg (x + 2πn).

1.
sin 390 = sin (360 + 30) = sin (2π + 30) = sin 30 = 1 2

2.
tg 780 = tg (720 + 60) = tg (4π + 60) = tg 60 = 3

3.
sin (390) = sin (390) = sin (2π + 30) = sin 30 = 1 2

4.
tg (210) = tg 210 = tg (π + 30) = tg 30 = 3 3 .

5.
cos 300 = cos ((60 2π)) = cos (60 2π) = cos 60 = 1 2

6.
sin 5π 3 = sin (2π π 3 ) = sin (π 3 2π) = sin π 3 = 3 2 .

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2021-11-09 09:20
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