Задание 13.16

Найдите sin (α β), если sin α = 4 5,π < α < 3π 2 и cos β = 7 25 3π 2 < β < 2π

Answers

sin 2β = 1 cos 2β = 1 49 625 = 526 625β IV  ч.  sin β = 24 25 cos 2α = 1 sin 2α = 1 16 25 = 9 25α III ч.  cos α = 3 5 sin (α β) = sin αcos β cos αsin β = 4 5 7 25 (24 25 (3 5 )) = = 28 125 72 125 = 100 125 = 4 5.

Ответ: sin (α β) = 4 5.

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2021-11-20 11:24
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