Задание 16.5

Question

16.5. $^{\circ}$ Решите уравнение:
1) $\operatorname{tg} x=\sqrt{3}$
2) $\operatorname{tg} x=-\frac{\sqrt{3}}{3}$
3) $\operatorname{tg} x=-1$
4) $\operatorname{tg} x=5$

Gimli · Accepted Answer

$$
\begin{array}{l}
16.5 \
1) \operatorname{tg} x=\sqrt{3} \
x=\operatorname{arctg} \sqrt{3}+\pi n \
x=\frac{\pi}{3}+\pi n, n \in z \
	ext { 2) } \operatorname{tg} x=-\frac{\sqrt{3}}{3} \
x=\operatorname{arctg}\left(-\frac{\sqrt{3}}{3}ight)+\pi n \
x=-\frac{\pi}{3}+\pi n, n \in z \
	ext { 3) } \operatorname{tg} x=-1 \
x=\operatorname{arctg}(-1)+\pi n \
x=-\frac{\pi}{4}+\pi n, n \in z \
	ext { 4) } \operatorname{tg} x=5 \
x=\operatorname{arctg} 5+\pi n, n \in z
\end{array}
$$

Задание 16.5

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Задание 16.5

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