Задание 16.6

Question

$^{\circ}$ Решите уравнение:
$$1) \operatorname{tg} x=1$$
$$2) \operatorname{tg} x=\frac{\sqrt{3}}{3}$$
$$3) \operatorname{tg} x=-\sqrt{3}$$
$$4) \operatorname{tg} x=-2$$

Gimli · Accepted Answer

$16.6$
1) $\operatorname{tg} x=1$ 
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$x=\operatorname{arctg} 1+\pi n$ 
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$ x=\frac{\pi}{4}+\pi n$
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2) $\operatorname{tg} x=\frac{\sqrt{3}}{3}$
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$x=\operatorname{arctg} \frac{\sqrt{3}}{3}+\pi n$
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$ x=\frac{\pi}{6}+\pi n$ 
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3) $\operatorname{tg} x=-\sqrt{3}$
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$ x=\operatorname{arctg}(-\sqrt{3})+\pi n$ 
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$x=-\operatorname{arctg} \sqrt{3}+\pi n $
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$x=-\frac{\pi}{3}+\pi n$
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4) $\operatorname{tg} x=-2$
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$ x=-\operatorname{arctg} 2+\pi n $

Задание 16.6

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Задание 16.6

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