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Exercise 1.3.4
Finally, consider the case . In this case has roots and , which are real and distinct.
- (a)
- Show that the graph of has a local minimum at and a local maximum at . Thus is a local minimum value and is a local maximum value. Also show that .
- (b)
- Explain why has three real roots if and have opposite signs and has one real root if they have the same sign. Illustrate your answer with a drawing of the three cases that can occur.
- (c)
- Conclude that has three real roots if and only if .
- (d)
- Finally, use part (c) of Exercise 1 to show that the roots are all real if and only if .
Answers
Proof. Case .
- (a)
-
.
is strictly increasing on and on , strictly decreasing on . is a local maximum, and a local minimum. As is decreasing on , .
- (b)
-
As
is continuous, and
,
and
strictly monotonous on each interval
, the intermediate value theorem gives three roots if
, and a unique root if
.
If , then (Ex.1 c), which we can exclude by hypothesis.
- (c)
- As these cases are mutually exclusive, (b) proves that has 3 real roots iff .
- (d)
-
By Ex. 1.3.2 and 1.3.3, we know that
imply that
has a unique real root.
If has 3 distinct real roots, then (Ex.1.2.4), , and (c) shows that , thus .
Conversely, if , then and . By (c), we know that has 3 real roots.
Conclusion : has three distinct real roots iff .