Exercise 1.3.4

Finally, consider the case p < 0 . In this case f ( y ) = 3 y 2 + p has roots α = p 3 and β = p 3 , which are real and distinct.

(a)
Show that the graph of f ( y ) has a local minimum at α and a local maximum at β . Thus f ( α ) is a local minimum value and f ( β ) is a local maximum value. Also show that f ( α ) < f ( β ) .
(b)
Explain why f ( y ) has three real roots if f ( α ) and f ( β ) have opposite signs and has one real root if they have the same sign. Illustrate your answer with a drawing of the three cases that can occur.
(c)
Conclude that f ( y ) has three real roots if and only if f ( α ) f ( β ) < 0 .
(d)
Finally, use part (c) of Exercise 1 to show that the roots are all real if and only if Δ > 0 .

Answers

Proof. Case p < 0 .

(a)
f ( y ) = 3 y 2 + p < 0 y 2 < p 3 β < f ( y ) < α ( α = p 3 = β ) .

f is strictly increasing on ] , β ] and on [ α , + [ , strictly decreasing on [ β , α ] . β is a local maximum, and α a local minimum. As f is decreasing on [ β , α ] , f ( β ) > f ( α ) .

(b)
As f is continuous, and lim y + f ( y ) = + , lim y f ( y ) = and f strictly monotonous on each interval ] , β ] , [ β , α ] , [ α , + [ , the intermediate value theorem gives three roots if f ( α ) f ( β ) < 0 , and a unique root if f ( α ) f ( β ) > 0 .

If f ( α ) f ( β ) = 0 , then Δ = 27 f ( α ) f ( β ) = 0 (Ex.1 c), which we can exclude by hypothesis.

(c)
As these cases are mutually exclusive, (b) proves that f has 3 real roots iff f ( α ) f ( β ) < 0 .
(d)
By Ex. 1.3.2 and 1.3.3, we know that p 0 imply that f has a unique real root.

If f has 3 distinct real roots, then Δ 0 (Ex.1.2.4), p < 0 , and (c) shows that f ( α ) f ( β ) < 0 , thus Δ = 27 f ( α ) f ( β ) > 0 .

Conversely, if Δ > 0 , then p < 0 and f ( α ) f ( β ) < 0 . By (c), we know that f has 3 real roots.

Conclusion : f has three distinct real roots iff Δ > 0 .

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2022-07-19 00:00
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