Exercise 10.3.14

As explained in [21](C.R.Videla, On points constructible from conics), Pappus used intersections of conics to trisect angles as follows. Consider the unit circle centered at the origin, and let 0 < 𝜃 < π 2 . Then P = ( cos 𝜃 , sin 𝜃 ) is the corresponding point on the unit circle. We assume that P is known. Also let O = ( 0 , 0 ) and set A = ( 1 , 0 ) . Thus 𝜃 = ∠POA .

(a)
Consider the curve C consisting of all points Q = ( x , y ) such that the distance from P to Q is twice the distance from Q to the x -axis. The curve C intersects the unit circle at a point R lying in the interior of ∠POA . Prove that ∠ROA = 𝜃 3 .
(b)
Show that the curve C is a hyperbola. It follows that we have trisected an angle using the intersection of a hyperbola and a circle, i.e., an intersection of conics.

Answers

Proof.

(a)
Let H be the orthogonal projection of R on the x -axis, and S such that H is the midpoint of RS , so S is the reflection of R with regard to the x -axis. Since R is on the curve C , PR = 2 RH = RS ,

therefore the measures of ∠ROP and ∠SOR are equal, and is twice the measure of ∠AOR , so OR trisects the angle ∠POA and a measure of ∠ROA is 𝜃 3 .

(b)
Let Q = ( x , y ) , H = ( x , 0 ) , P = ( cos 𝜃 , sin 𝜃 ) Q C QP = 2 QH Q P 2 = 4 Q H 2 ( x cos 𝜃 ) 2 + ( y sin 𝜃 ) 2 = 4 y 2 x 2 3 y 2 2 x cos 𝜃 2 y sin 𝜃 + 1 = 0 .

The discriminant of the quadratic form a x 2 + bxy + c y 2 = x 2 3 y 2 is Δ = 12 > 0 , so C is not empty and C is a hyperbola.

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2022-07-19 00:00
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