Exercise 11.2.3

Use Theorem 11.2.4 to compute N 6 and N 36 .

Answers

Proof. By Theorem 11.2.4,

N n = 1 n m n μ ( m ) p n m .

N 6 = 1 6 ( μ ( 1 ) p 6 + μ ( 2 ) p 3 + μ ( 3 ) p 2 + μ ( 6 ) p ) = 1 6 ( p 6 p 3 p 2 + p )

The 9 = 3 × 3 factors d of 36 = 2 2 × 3 2 , and the corresponding values of μ ( d ) are

d 1 2 3 4 6 9 12 18 36 μ ( d ) 1 1 1 0 1 0 0 0 0

N 36 = 1 36 ( p 36 p 18 p 12 + p 6 )
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2022-07-19 00:00
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