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Exercise 13.3.2
Let , and let be the resolvent built from . Prove that .
Proof. Let be the symmetry group of and be representatives for the left cosets of in . The universal resolvent is . Since , for each , , hence the coefficients of are in , i.e., .
Suppose that , then . But the set is also a set of left coset representatives of in . Thus the application of has merely permuted the roots of leaving the coefficients fixed. It means that coefficients of are symmetric and are polynomials in with integers coefficients (cf. Ex.9.1.6), i.e., . The application of evaluation map to , so that , gives . □
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