Exercise 2.3.6

Find the quartic polynomial whose roots are obtained by adding 1 to each of the roots of x 4 + 3 x 2 + 4 x + 7 .

Answers

Proof. Let f = x 4 + 3 x 2 + 4 x + 7 = ( x x 1 ) ( x x 2 ) ( x x 3 ) ( x x 4 ) .

The polynomial whose roots are 1 + x 1 , 1 + x 2 , 1 + x 3 , 1 + x 4 is

g = ( x 1 x 1 ) ( x 1 x 2 ) ( x 1 x 3 ) ( x 1 x 4 ) = f ( x 1 ) = ( x 1 ) 4 + 3 ( x 1 ) 2 + 4 ( x 1 ) + 7 = x 4 4 x 3 + 6 x 2 4 x + 1 + 3 x 2 6 x + 3 + 4 x 4 + 7 = x 4 4 x 3 + 9 x 2 6 x + 7 .

If x 1 , x 2 , x 3 , x 4 are the roots of f , then x 1 + 1 , x 2 + 1 , x 3 + 1 , x 4 + 1 are the roots of

g = x 4 4 x 3 + 9 x 2 6 x + 7 .

User profile picture
2022-07-19 00:00
Comments