Exercise 4.4.9

Prove that α is an algebraic integer if and only if α .

Answers

Proof. If α , α is a root of the monic polynomial x α [ x ] , thus α is an algebraic integer.

Conversely, let α be an algebraic integer.

α = p q , ( p , q ) × , p q = 1 .

α is a root of f = x n + a n 1 x n 1 + + a 0 , where the coefficients a i are integers. Thus

( p q ) n + a n 1 ( p q ) n 1 + + a 0 = 0 ,

that is

p n + a n 1 p n 1 q + + a 0 q n = 0 .

This implies q p n , where q p = 1 , thus q p n = 1 . Hence q 1 , where q > 0 , thus q = 1 , and α = p q = p .

Conclusion: For all α , α is an algebraic integer iff α .

¯ = .

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2022-07-19 00:00
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