Exercise 5.2.2

Prove that an algebraic extension F L is normal if and only if for every α L , the minimal polynomial of α over F splits completely over L .

Answers

Proof. Let F L a normal extension. Let α L . Its minimal polynomial f F [ x ] is irreducible, thus this polynomial splits completely over F by definition of a normal extension.

Conversely, suppose that every α L is such that its minimal polynomial splits completely over F .

Let g F [ x ] any irreducible polynomial, and α a root of g in L . Then g is the minimal polynomial of α over L . So g splits completely over L by hypothesis. Hence every irreducible polynomial g which has a root in L splits completely over L . So the extension F L is normal. □

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2022-07-19 00:00
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