Exercise 5.3.13

Let F have characteristic p , and let F L be a finite extension with p [ L : F ] . Prove that F L is separable.

Answers

Proof.

Let α L , and f its minimal polynomial over F . Then F F ( α ) L , thus [ F ( α ) : F ] = deg ( f ) divides [ L : F ] . Consequently p deg ( f ) . By Lemma 5.3.6, this implies that f is separable. Hence every α L is separable over F . The extension F L is so separable. □

User profile picture
2022-07-19 00:00
Comments