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Exercise 6.2.3
Consider , where . By proposition 4.2.5, the minimal polynomial of over is .
- (a)
- Show that .
- (b)
- Show that is the splitting field of over , and conclude that is a group of order 20.
We will describe the structure of this Galois group in section 6.4.
Answers
Proof. Write .
- (a)
-
as
, Proposition 6.1.4(b) shows that
is uniquely determined by
.
Moreover by Proposition 6.4.1(a), is a root of , whose roots are , and is a root of , whose roots are .
Then Exercice 6.1.1 shows that
Moreover, by Exercise 5.1.8, .
- (b)
-
is the splitting field of the separable irreducible polynomial
over
. Indeed,
is irreducible over
by Schönemann-Eisenstein Criterion with
, and separable since its roots in
are
which are distinct.
By theorem 6.2.1, , therefore