Exercise 6.4.11

The goal of this exercise is to show that the group G of permutations (6.11) is metacyclic in the sense that G has a normal subgroup H such that H and G H are cyclic. Show that this follows from G AGL ( 1 , 𝔽 p ) together with (6.6) and proposition A.5.3.

Answers

Proof. If L = ( ζ p , 2 p ) , and G = Gal ( L ) , then by (6.4), G AGL ( 1 , 𝔽 p ) . By (6.6) and Exercise 9, AGL ( 1 , 𝔽 p ) T 𝔽 p , and T 𝔽 p . As 𝔽 p is a cyclic (additive) group, and 𝔽 p a cyclic (multiplicative) group by Proposition A.5.3, G = Gal ( L ) is metacyclic. □

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2022-07-19 00:00
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