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Exercise 8.5.3
Let have characteristic and suppose that has degree and is not separable. Prove that is solvable by radicals over .
Answers
Proof. By Proposition 5.3.8, has the same roots as . The splitting field of over is so the splitting field of the separable polynomial . As , is solvable over by Proposition 8.5.4. We can conclude that all polynomial of degree , separable or not, is solvable by radicals over . □