Exercise 8.5.3

Let F have characteristic 0 and suppose that f F [ x ] has degree 4 and is not separable. Prove that f is solvable by radicals over F .

Answers

Proof. By Proposition 5.3.8, f has the same roots as g = f pgcd ( f , f ) . The splitting field L of f over F is so the splitting field of the separable polynomial g . As deg ( g ) deg ( f ) 4 , L is solvable over F by Proposition 8.5.4. We can conclude that all polynomial f F [ x ] of degree n 4 , separable or not, is solvable by radicals over F . □

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2022-07-19 00:00
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