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Exercise 8.6.3
Show that the polynomial of Example 8.6.7 is irreducible over and has four real roots.
Answers
Proof. By Gauss Lemma (Theorem A.3.2), it is sufficient to prove that has no non trivial factorization in . Since the reduction modulo 2 of is is of the same degree, it is sufficient to prove that is irreducible in (a non trivial factorization in would give a factorisation in by projection). This is the case if has no root in (an irreducible factor of of degree 2 would give a root of in ).
As any element satisfies , , so is irreducible over . Therefore
is irreducible over
. As is continuous, the Intermediate Value Theorem shows the existence of the roots . As , has no other root, so all the roots of are real. □