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Exercise 1.7.21 (The group of rigid motions of a cube is isomorphic to $S_4$)
Show that the group of rigid motions of a cube is isomorphic to . [This group acts on the set of four pairs of opposite vertices.]
Answers
(See the figure, and complements, in the solution of Exercise 7.5.10 of “Cox, Galois Theory” on this site)
Proof. Consider the cube with vertices
Let be the group of rigid motions of a cube. Every rigid motion gives a permutation of the 8 vertices of the cube, thus fixes their gravity center , so is an axial rotation, or .
We give an arbitrary numbering of the four long diagonals (pairs of opposite vertices):
Since is an isometry, , hence the pair is a long diagonal, and it is the same for the other long diagonals. Therefore acts on the set
of the four long diagonals by
The associate permutation representation is
We search the kernel of . if and only if
so maps the four lines containing the long diagonals on themselves.
Assume, for the sake of contradiction, that . Then is an axial rotation. If every vertex maps to the opposite vertice, then is the symmetry through ( and are affine transformations which send at least non coplanar points on the same images). But is not a rigid motion. Therefore there is some long diagonal such that . Then the axis of the rotation is , a long diagonal. The only lines globally invariant by such a rotation are the axis, and perhaps the lines in the orthogonal plane (if is a rotation of radians). Therefore the 3 others long diagonals, which are fixed by , would be orthogonal to the axis, but the four diagonals are not mutually orthogonal. This contradiction shows that , so
Therefore is injective (the action is faithful) and .
Since , . We prove in Exercise 1.2.10 that . Therefore is bijective: it is an isomorphism, so
(another proof is given in Exercise 7.5.10 of “Cox, Galois Theory”) □