Homepage Solution manuals David S. Dummit Abstract Algebra Exercise 2.3.5 (Number of generators for $\mathbb{Z}/49000\, \mathbb{Z}$.)

Exercise 2.3.5 (Number of generators for $\mathbb{Z}/49000\, \mathbb{Z}$.)

Find the number of generators for 49000 .

Answers

Proof. The number of generators for 49000 is

φ ( 49000 ) = φ ( 2 3 5 3 7 2 ) = ( 2 3 2 2 ) ( 5 3 5 2 ) ( 7 2 7 ) = 4 100 42 = 16800 .
sage: euler_phi(49000)
16800

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2025-10-16 10:17
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