Homepage Solution manuals David S. Dummit Abstract Algebra Exercise 3.5.6 ($\langle (1\ 3), (1\ 2 \ 3 \ 4) \rangle \simeq D_8$)

Exercise 3.5.6 ($\langle (1\ 3), (1\ 2 \ 3 \ 4) \rangle \simeq D_8$)

Show that ( 1 3 ) , ( 1 2 3 4 ) is a proper subgroup of S 4 . What is the isomorphism type of this subgroup?

Answers

Proof. Put σ = ( 1 2 3 4 ) and τ = ( 1 3 ) . Then

σ 4 = τ 2 = 1 , 𝜎𝜏 = τ σ 1 .

Since D 8 = r , s r 4 = s 2 = 1 , 𝑟𝑠 = s r 1 , there is a surjective homomorphism φ : D 8 σ , τ such that φ ( r ) = σ and φ ( s ) = τ . Therefore | σ , τ | | D 8 | = 8 . Moreover,

σ , τ { 1 , σ , σ 2 , σ 3 , τ , 𝜏𝜎 , τ σ 2 , τ σ 3 } ,

where these 8 permutations are distinct, so | σ , τ | 8 . This shows that | σ , τ | = 8 , therefore φ is an isomorphism, so

( 1 3 ) , ( 1 2 3 4 ) D 8 .

(Alternatively, If we choose the numbering 1 , 2 , 3 , 4 to the vertices of a square as in the figure p. 24, then σ corresponds to the rotation of angle π 2 , and τ to the reflection about the line ( 2 , 4 ) . These two geometric transformations are generators of D 8 .) □

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2025-12-19 10:19
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