Homepage Solution manuals David S. Dummit Abstract Algebra Exercise 4.3.20 ( All elements in the conjugacy class of $\sigma$ in $S_n$ are conjugate in $A_n$ if and only if $\sigma$ commutes with an odd permutation)

Exercise 4.3.20 ( All elements in the conjugacy class of $\sigma$ in $S_n$ are conjugate in $A_n$ if and only if $\sigma$ commutes with an odd permutation)

Let σ A n . Show that all elements in the conjugacy class of σ in S n (i.e., all elements of the same cycle type as σ ) are conjugate in A n if and only if σ commutes with an odd permutation. [Use the preceding exercise.]

Answers

Proof. Suppose that σ A n commutes with an odd permutation τ . Then τ C S n ( σ ) and τ A n . Therefore

A n C S n ( σ ) A n :

indeed, τ = 1 τ A n C S n ( σ ) , but τ A n .

Since A n is a maximal subgroup of S n , and A n A n C S n ( σ ) S n , where A n C S n ( σ ) A n , we obtain

A n C S n = S n .

If we apply the result of Exercise 19, with G = S n , H = A n S n and x = σ , then the number k of orbits of A n acting by conjugation on conjugacy class 𝒦 of σ is given by

k = | G : H C G ( x ) | = | S n : A n C S n ( σ ) | = 1 .

Since k = 1 the orbits of σ for the actions of G and of H are the same:

{ 𝜆𝜎 λ 1 λ A n } = { 𝜆𝜎 λ 1 λ S n } ,

so all elements in the conjugacy class of σ in S n are conjugate in A n .

Conversely, suppose that all elements in the conjugacy class of σ in S n are conjugate in A n , so that k = 1 , where k is the number of conjugacy classes of σ for the action of A n in the conjugacy class 𝒦 of σ for the action of S n . By Exercise 19,

k = 1 = | S n : A n C S n ( σ ) | ,

therefore

A n C S n ( σ ) = S n .

Hence C S n ( σ ) A n (otherwise A n = S n ), so there exists a permutation τ S n A n such that τ C S n ( σ ) , i.e., τ is an odd permutation which commutes with σ .

In conclusion, all elements in the conjugacy class of σ in S n are conjugate in A n if and only if σ commutes with an odd permutation. □

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2026-02-08 08:40
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