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Problem 5.4.14 (Group of upper triangular matrices all of whose diagonal entries are equal)

Let G = { ( a 𝑖𝑗 ) ∈ GL n ( F ) ∣ a 𝑖𝑗 = 0  if  i > j ,  and  a 11 = a 22 = ⋯ = a 𝑛𝑛 } , where F is a field, be the group of upper triangular matrices all of whose diagonal entries are equal. Prove that G ≃ D × U , where D is the group of all nonzero multiples of the identity matrix and U is the group of upper triangular matrices with 1 ’s down the diagonal.

Answers

Proof.

  • First G = 𝐷𝑈 : if M = ( a 𝑖𝑗 ) ∈ G , then a 11 = a 22 = ⋯ = a 𝑛𝑛 = a for some a ∈ F , and

    M = ( a I n ) ( a − 1 M ) ,

    where a I n ∈ D and a − 1 M ∈ U .

  • D ∩ U = { I n } : if M ∈ D ∩ U , then M = a I n for some a ∈ F , and a = 1 since M ∈ U , so M = I n .
  • Every element M = a I n of D commutes with every element N of U .

    If P = 𝑀𝑁 is any element of G = 𝐷𝑈 , where M ∈ D and N ∈ U , then for every V ∈ U ,

    𝑃𝑉 P − 1 = N − 1 ( M − 1 V M ) N = N − 1 V N ∈ U ,

    so U ⊴ G , and similarly D ⊴ G .

By Theorem 9,

G = 𝐷𝑈 ≃ D × U .

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2026-09-10 12:04
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