Exercise 1.1.10

Question

Which point of the cube is $i+j$ ? Which point is the vector sum of $i=(1,0,0)$ and $\boldsymbol{j}=(0,1,0)$ and $\boldsymbol{k}=(0,0,1)$ ? Describe all points $(x, y, z)$ in the cube.

Prakash Anand · Accepted Answer

$\boldsymbol{i}-\boldsymbol{j}=(1,1,0)$ is in the base $(x-y$ plane). $\boldsymbol{i}+\boldsymbol{j}+\boldsymbol{k}=(1,1,1)$ is the opposite corner from $(0,0,0)$. Points in the cube have $0 \leq x \leq 1,0 \leq y \leq 1,0 \leq z \leq 1$.

Exercise 1.1.10

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Exercise 1.1.10

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