Exercise 1.2.22

Answers

v12w12 + 2v1w1v2w2 + v22w22 v12w12 + v12w22 + v22w12 + v22w22 is true (cancel 4 terms) because the difference is v12w22 + v22w12 2v1w1v2w2 which is (v1w2 v2w1) 2 0

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2021-11-20 14:08
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