Homepage › Solution manuals › Gilbert Strang › Introduction to Linear Algebra › Exercise 1.2.25

Exercise 1.2.25

Answers

The cosine of $𝜃$ is $x ∕ \sqrt{x^{2} + y^{2}}$ , near side over hypotenuse. Then $| \cos 𝜃 |^{2}$ is not greater than 1: $x^{2} ∕ (x^{2} + y^{2}) \leq 1$

mathchakra

2021-11-20 14:08

Exercise 1.2.25

Answers

Comments

Add answer