Exercise 1.2.7

Answers

(a) $\cos 𝜃 = v \cdot w ∕ ∥ v ∥ ∥ w ∥ = 1 ∕ (2) (1)$ so $𝜃 = 6 0^{∘}$ or $π ∕ 3$ radians

(b) $\cos 𝜃 =$ 0 so $𝜃 = 9 0^{∘}$ or $π ∕ 2$ radians

(c) $\cos 𝜃 = 2 ∕ (2) (2) = 1 ∕ 2$ so $𝜃 = 6 0^{∘}$ or $π ∕ 3$ (d) $\cos 𝜃 = - 1 ∕ \sqrt{2}$ so $𝜃 = 13 5^{∘}$ or $3 π ∕ 4$ .

mathchakra

2021-11-20 14:02