Exercise 1.3.10

Answers

\begin{matrix} z_{2} - z_{1} = b_{1} & z_{1} = - b_{1} - b_{2} - b_{3} \\ z_{3} - z_{2} = b_{2} & z_{2} = - b_{2} - b_{3} & = [\begin{matrix} - 1 & - 1 & - 1 \\ 0 & - 1 & - 1 \\ 0 & 0 & - 1 \end{matrix}] \\ 0 - z_{3} = b_{3} & z_{3} = - b_{3} \end{matrix} [\begin{matrix} b_{1} \\ b_{2} \\ b_{3} \end{matrix}] = Δ^{- 1} b

mathchakra

2021-11-20 14:15