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Exercise 1.3.4

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The combination $0 w_{1} + 0 w_{2} + 0 w_{3}$ always gives the zero vector, but this problem looks for other zero combinations (then the vectors are dependent, they lie in a plane): $w_{2} = (w_{1} + w_{3}) ∕ 2$ so one combination that gives zero is $w_{1} - 2 w_{2} + w_{3} = 0$

mathchakra

2021-11-20 14:13

Exercise 1.3.4

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