Exercise 1.3.6

Answers

\begin{aligned} c = 3 ⟹ & [\begin{matrix} 1 & 1 & 0 \\ 3 & 2 & 1 \\ 7 & 4 & 3 \end{matrix}] has column 3 = column 1 - column 2 \\ c = - 1 ⟹ & [\begin{matrix} 1 & 0 & - 1 \\ 1 & 1 & 0 \\ 0 & 1 & 1 \end{matrix}] has column 3 = - column 1 + column 2 \\ c = 0 ⟹ & [\begin{matrix} 0 & 0 & 0 \\ 2 & 1 & 5 \\ 3 & 3 & 6 \end{matrix}] has column 3 = 3 (column 1) - column 2 \end{aligned}

mathchakra

2021-11-20 14:14