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Exercise 2.1.8

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Four planes in 4 -dimensional space normally meet at a point. The solution to $Ax =$ $(3, 3, 3, 2)$ is $x = (0, 0, 1, 2)$ if $A$ has columns $(1, 0, 0, 0), (1, 1, 0, 0), (1, 1, 1, 0)$ $(1, 1, 1, 1) .$ The equations are $x + y + z + t = 3, y + z + t = 3, z + t = 3, t = 2 .$ Solve them in reverse order!

mathchakra

2021-11-20 14:38

Exercise 2.1.8

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