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Introduction to Linear Algebra

Exercise 2.2.13

Answers

\begin{aligned} 2 x - 3 y = 3 & 2 x - 3 y = 3 & 2 x - 3 y = 3 & x = 3 \\ 4 x - 5 y + z = 7 & gives & y + z = 1 & and & y + z = 1 & and & y = 1 \\ 2 x - y - 3 z = 5 & 2 y + 3 z = 2 & - 5 z = 0 & z = 0 \end{aligned}

Here are steps $1, 2, 3$ : Subtract $2 \times$ row 1 from row 2 , subtract $1 \times$ row 1 from row 3, subtract $2 \times$ row 2 from row 3.

mathchakra

2021-11-20 15:02

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