Homepage › Solution manuals › Gilbert Strang › Introduction to Linear Algebra › Exercise 2.2.19

Exercise 2.2.19

Answers

Row 2 becomes $3 y - 4 z = 5$ , then row 3 becomes $(q + 4) z = t - 5$ . If $q = - 4$ the system is singular-no third pivot. Then if $t = 5$ the third equation is $0 = 0$ which allows infinitely many solutions. Choosing $z = 1$ the equation $3 y - 4 z = 5$ gives $y = 3$ and equation 1 gives $x = - 9$ .

mathchakra

2021-11-20 15:06

Exercise 2.2.19

Answers

Comments

Add answer