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Exercise 2.2.23

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If ordinary elimination leads to $x + y = 1$ and $2 y = 3$ , the original second equation could be $2 y + ℓ (x + y) = 3 + ℓ$ for any $ℓ$ . Then $ℓ$ will be the multiplier to reach $2 y = 3$ , by subtracting $ℓ$ times equation 1 from equation 2 .

mathchakra

2021-11-20 15:07

Exercise 2.2.23

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