Exercise 2.3.20

Answers

(a) Each column of $EB$ is $E$ times a column of $B$

(b)

[\begin{matrix} 1 & 0 \\ 1 & 1 \end{matrix}] [\begin{matrix} 1 & 2 & 4 \\ 1 & 2 & 4 \end{matrix}] = [\begin{matrix} 1 & 2 & 4 \\ 2 & 4 & 8 \end{matrix}] .

All rows of $EB$ are multiples of

[\begin{matrix} 1 & 2 & 4 \end{matrix}] .

mathchakra

2021-11-20 15:20