Exercise 2.3.24

Answers

[\begin{matrix} A & b \end{matrix}] = [\begin{matrix} 2 & 3 & 1 \\ 4 & 1 & 17 \end{matrix}] \to [\begin{matrix} 2 & 3 & 1 \\ 0 & - 5 & 15 \end{matrix}] .

The triangular system is

\begin{array}{l} 2 x_{1} + 3 x_{2} & = 1 \\ - 5 x_{2} & = 15 \end{array}

Back substitution gives $x_{1} = 5$ and $x_{2} = - 3$ .

mathchakra

2021-11-20 15:21