Exercise 2.4.10

Answers

We have,

FA = [\begin{matrix} a + c & b + d \\ c & d \end{matrix}]

and then

E (FA) = [\begin{matrix} a + c & b + d \\ a + 2 c & b + 2 d \end{matrix}] .

$E (FA)$ is not the same as $F (EA)$ because multiplication is not commutative: $EF \neq FE$ .

mathchakra

2021-12-06 17:30