Exercise 2.4.14

Answers

We have

{(A - B)}^{2} = {(B - A)}^{2} = A (A - B) - B (A - B) = A^{2} - AB - BA + B^{2} .

In a typical case (when $AB \neq BA$ ) the matrix $A^{2} - 2 AB + B^{2}$ is different from ${(A - B)}^{2}$ .

mathchakra

2021-12-06 17:33