Exercise 2.4.22

Answers

Matrix $A$ given by

A = [\begin{matrix} 0 & 1 \\ - 1 & 0 \end{matrix}]

has $A^{2} = - I$ ;

BC = [\begin{matrix} 1 & - 1 \\ 1 & - 1 \end{matrix}] [\begin{matrix} 1 & 1 \\ 1 & 1 \end{matrix}] = [\begin{matrix} 0 & 0 \\ 0 & 0 \end{matrix}];

Also,

DE = [\begin{matrix} 0 & 1 \\ 1 & 0 \end{matrix}] [\begin{matrix} 0 & 1 \\ - 1 & 0 \end{matrix}] = [\begin{matrix} - 1 & 0 \\ 0 & 1 \end{matrix}] = - ED .

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mathchakra

2021-12-06 17:44