Exercise 2.4.24

Answers

{(A_{1})}^{n} = [\begin{matrix} 2^{n} & 2^{n} - 1 \\ 0 & 1 \end{matrix}],

${(A_{2})}^{n} = 2^{n - 1} [\begin{matrix} 1 & 1 \\ 1 & 1 \end{matrix}],$

${(A_{3})}^{n} = [\begin{matrix} a^{n} & a^{n - 1} b \\ 0 & 0 \end{matrix}] .$

mathchakra

2021-12-06 17:47