Exercise 2.5.10

Answers

We have

A^{- 1} = [\begin{matrix} 0 & 0 & 0 & 1 ∕ 5 \\ 0 & 0 & 1 ∕ 4 & 0 \\ 0 & 1 ∕ 3 & 0 & 0 \\ 1 ∕ 2 & 0 & 0 & 0 \end{matrix}]

and

B^{- 1} = [\begin{matrix} 3 & - 2 & 0 & 0 \\ - 4 & 3 & 0 & 0 \\ 0 & 0 & 6 & - 5 \\ 0 & 0 & - 7 & 6 \end{matrix}]

(invert each block of $B$ ).

mathchakra

2021-12-19 17:02