Exercise 2.5.22

Answers

\begin{aligned} [\begin{matrix} 1 & 3 & 1 & 0 \\ 2 & 7 & 0 & 1 \end{matrix}] \to [\begin{matrix} 1 & 3 & 1 & 0 \\ 0 & 1 & - 2 & 1 \end{matrix}] \to [\begin{matrix} 1 & 0 & 7 & - 3 \\ 0 & 1 & - 2 & 1 \end{matrix}] = [\begin{matrix} I & A^{- 1} \end{matrix}]; \\ [\begin{matrix} 1 & 4 & 1 & 0 \\ 3 & 9 & 0 & 1 \end{matrix}] \to [\begin{matrix} 1 & 4 & 1 & 0 \\ 0 & - 3 & - 3 & 1 \end{matrix}] \to [\begin{matrix} 1 & 0 & - 3 & 4 ∕ 3 \\ 0 & 1 & 1 & - 1 ∕ 3 \end{matrix}] = [\begin{matrix} I & A^{- 1} \end{matrix}] . \end{aligned}

mathchakra

2021-12-19 17:11