Exercise 2.5.27

Answers

A^{- 1} = [\begin{matrix} 1 & 0 & 0 \\ - 2 & 1 & - 3 \\ 0 & 0 & 1 \end{matrix}]

(notice the sign changes);

A^{- 1} = [\begin{matrix} 2 & - 1 & 0 \\ - 1 & 2 & - 1 \\ 0 & - 1 & 1 \end{matrix}] .

mathchakra

2021-12-19 17:35