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Introduction to Linear Algebra

Exercise 2.5.6

Answers

(a)

Multiply

AB = AC

by

A^{- 1}

to find

B = C

(since

A

is invertible)

(b)

As long as

B - C

has the form

[\begin{matrix} x & y \\ - x & - y \end{matrix}],

we have $AB = AC$ for

A = [\begin{matrix} 1 & 1 \\ 1 & 1 \end{matrix}] .

mathchakra

2021-12-19 16:59

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