Exercise 2.6.11

Answers

\begin{aligned} A = [\begin{matrix} 2 & 4 & 8 \\ 0 & 3 & 9 \\ 0 & 0 & 7 \end{matrix}] has L = I (A is already upper triangular) and D = [\begin{matrix} 2 \\ 3 \\ 7 \end{matrix}]; \\ A = LU has U = A; A = LDU has U = D^{- 1} A = [\begin{matrix} 1 & 2 & 4 \\ 0 & 1 & 3 \\ 0 & 0 & 1 \end{matrix}] with 1’s on the diagonal. \end{aligned}

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2021-12-20 21:04