Exercise 2.6.19

Answers

We have

[\begin{matrix} 1 \\ 1 & 1 \\ 0 & 1 & 1 \end{matrix}] [\begin{matrix} 1 & 1 & 0 \\ 1 & 1 \\ 1 \end{matrix}] = LIU;

and

[\begin{matrix} a & a & 0 \\ a & a + b & b \\ 0 & b & b + c \end{matrix}] = L [\begin{matrix} a \\ b \\ c \end{matrix}] U .

A tridiagonal matrix $A$ has bidiagonal factors $L$ and $U$ .

mathchakra

2021-12-20 21:13