Exercise 2.6.4

Answers

We have

L c = [\begin{matrix} 1 \\ 1 & 1 \\ 1 & 2 & 1 \end{matrix}] [\begin{matrix} 5 \\ 2 \\ 2 \end{matrix}] = [\begin{matrix} 5 \\ 7 \\ 11 \end{matrix}];

and

U x = [\begin{matrix} 1 & 1 & 1 \\ 1 & 2 \\ 1 \end{matrix}] [x] = [\begin{matrix} 5 \\ 2 \\ 2 \end{matrix}];

Hence,

x = [\begin{matrix} 5 \\ - 2 \\ 1 \end{matrix}] .

mathchakra

2021-12-20 20:51