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Exercise 2.7.14

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The "reverse identity" $P$ takes $(1, \dots, n)$ into $(n, \dots, 1) .$ When rows and also columns are reversed, the 1,1 and $n, n$ entries of $A$ change places in $PAP .$ So do the $1, n$ and $n, 1$ entries. In general ${(PAP)}_{ij}$ is ${(A)}_{n - i + 1, n - j + 1}$ .

mathchakra

2022-01-16 12:22

Exercise 2.7.14

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