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Introduction to Linear Algebra

Exercise 2.7.17

Answers

(a)

The matrix

S = [\begin{matrix} 1 & 1 \\ 1 & 1 \end{matrix}] = S^{T}

is not invertible.

(b)

The matrix

S = [\begin{matrix} 0 & 1 \\ 1 & 1 \end{matrix}]

needs row exchange.

(c)

The matrix

S = [\begin{matrix} 1 & 1 \\ 1 & 0 \end{matrix}]

has pivots

D = [\begin{matrix} 1 & 0 \\ 0 & - 1 \end{matrix}] .

Therefore, no real square root.

mathchakra

2022-01-16 12:25

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