Exercise 2.7.1

Answers

A = [ 10 9 3 ]has AT = [ 19 0 3 ],A1 = [ 1 0 3 13 ], (A1) T = (AT) 1 = [ 1 3 0 13 ]; A = [ 1c c 0 ]has AT = A and A1 = 1 c2 [ 0c c 1 ] = (A1) T.

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2021-12-20 21:24
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