Exercise 2.7.22

Answers

We have

[\begin{matrix} 1 \\ 1 \\ 1 \end{matrix}] A = [\begin{matrix} 1 \\ 0 & 1 \\ 2 & 3 & 1 \end{matrix}] [\begin{matrix} 1 & 0 & 1 \\ 1 & 1 \\ - 1 \end{matrix}];

and

[\begin{matrix} 1 \\ 1 \\ 1 \end{matrix}] A = [\begin{matrix} 1 \\ 1 & 1 \\ 2 & 0 & 1 \end{matrix}] [\begin{matrix} 1 & 2 & 0 \\ - 1 & 1 \\ 1 \end{matrix}]

mathchakra

2022-01-16 12:30